(2t^3+t^2-5t+2)/(t+5)

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Solution for (2t^3+t^2-5t+2)/(t+5) equation:


D( t )

t+5 = 0

t+5 = 0

t+5 = 0

t+5 = 0 // - 5

t = -5

t in (-oo:-5) U (-5:+oo)

(2*t^3+t^2-(5*t)+2)/(t+5) = 0

(2*t^3+t^2-5*t+2)/(t+5) = 0

2*t^3+t^2-5*t+2 = 0

2*t^3+t^2-5*t+2 = 0

{ 1, -1, 2, -2 }

1

t = 1

2*t^3+t^2-5*t+2 = 0

1

t-1

2*t^2+3*t-2

2*t^3+t^2-5*t+2

t-1

2*t^2-2*t^3

3*t^2-5*t+2

3*t-3*t^2

2-2*t

2*t-2

0

2*t^2+3*t-2 = 0

DELTA = 3^2-(-2*2*4)

DELTA = 25

DELTA > 0

t = (25^(1/2)-3)/(2*2) or t = (-25^(1/2)-3)/(2*2)

t = 1/2 or t = -2

t in { -2, 1/2, 1}

(t+2)*(t-1/2)*(t-1) = 0

((t+2)*(t-1/2)*(t-1))/(t+5) = 0

( t+2 )

t+2 = 0 // - 2

t = -2

( t-1/2 )

t-1/2 = 0 // + 1/2

t = 1/2

( t-1 )

t-1 = 0 // + 1

t = 1

t in { -2, 1/2, 1 }

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